27y^2=12

Solution for 27y^2=12 equation:

27y^2=12

We move all terms to the left:

27y^2-(12)=0

a = 27; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·27·(-12)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*27}=\frac{-36}{54}
=-2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*27}=\frac{36}{54}
=2/3
$